Let AB represent an object placed at right angles to the principal axis at a distance greater than the focal length f of the convex lens. The image A1B1 is formed beyond 2F2 and is real and inverted.
OA = Object distance = u
OA1 = Image distance = v
OF2 = Focal length = f
OAB and OA1B1 are similar
But we know that OC = AB
the above equation can be written as
From equation (1) and (2), we get
Dividing equation (3) throughout by uvf
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